the distance between the point (b cosA,b sinA) from the origin
Answers
Answered by
1
We have the formula for the distance of a point(x,y) from origin =√x^2+y^2
The point is (bcosA,bSinA)
So the distance is √b^2cos^2A+b^2sin^2A
=√b^2(cos^2A+sin^2A)
=√b^2
=b.
Hope this helps
The point is (bcosA,bSinA)
So the distance is √b^2cos^2A+b^2sin^2A
=√b^2(cos^2A+sin^2A)
=√b^2
=b.
Hope this helps
vaniR:
Please mark as brainliest
Similar questions