Question

The distance between the point P (1,4) and Q (4,0) is?

Answer 1

Given,

Two points P (1,4) and Q (4,0).

To Find,

The distance between these two points.

Solution,

The formula for calculating the distance between two points is

Distance = √((x₂-x₁)²+(y₂-y₁)²)

The given points are (1,4) and (4,0)

here, x₂= 4, x₁=1, y₂=0 and y₁=4

So,

Distance = √((4-1)²+(0-4)²)

Distance = √(9)+(16)

Distance = √25

Distance = 5

Hence, the distance between points P (1,4) and Q (4,0) is 5 units.

Answer 2

Concept

The formula of the distance between

$y=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Where starting $(x_1,x_2)$ and $(y_1,y_2)$.

Given

Two points P (1,4) and Q (4,0).

To Find

The distance between these two points.

Solution

The formula for calculating the distance between two points is

Distance $=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The given points are (1,4) and (4,0)

here, x₂= 4, x₁=1, y₂=0 and y₁=4

So,

Distance $=\sqrt{(4-1)^2+(0-4)^2}$

Distance $=\sqrt{3^2+4^2}$

Distance $=\sqrt{25}$

Distance = 5

Hence, the distance between points P (1,4) and Q (4,0) is 5 units.