the distance between the point p=(1,6,5) and q= (2,5,-4) is? 83 units,√83 units ,9 units,non of these
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plz give the answer correct dont spoil the question
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The distance between the two points is √83 units
Given:
Points P (1, 6, 5) and Q (2, 5, -4)
To find:
The distance between the points P (1, 6, 5) and Q (2, 5, -4)
Solution:
Formula used:
The distance between two points is given by
d = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²]
From the data
Points P = (1, 6, 5) and Q = (2, 5, -4)
Using the formula distance between P and Q can be calculated as follows
=> PQ = √[(2 - 1)² + (5 - 6)² + (-4 - 5)²]
=> PQ = √[(1)² + (-1)² + (-9)²]
=> PQ = √[1+ 1 + 81 ]
=> PQ = √[83]
=> PQ = √83
Therefore,
The distance between the two points is √83 units
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