The distance between the point P(6,0) and Q ( -2 ,0) is
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Answer:
- 8 units is required distance between P & Q.
Explanation:
According to the Question
Given Points
Coordinate of P ( 6 ,0)
- Coordinate of Q ( -2 , 0)
We have to calculate the distance between these point.
Using Distance Formula
- PQ = √(x₂-x₁)² + (y₂-y₁)²
On substituting the value we get
↠ PQ = √(-2-6)² + (0-0)²
↠ PQ = √(-8)² + (0)²
↠ PQ = √64 + 0
↠ PQ = √64
↠ PQ = 8 units
- Hence, the distance between P& Q is 8 units.
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