Question

The distance between the points (0,7) and (_7,0) is​

Answer 1

distance = √x² + y²

= √49 + 49

= 7√2

Answer 2

Answer:

10 units is the required distance between the points (0,7) and (-7,0)

Step-by-step explanation:

Explanation:

Given two points (0,7) and (-7,0).

And we know that, if two points ($x_1 , y_1$) and ($x_2 , y_2$) are given than,

distance formula  = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Step 1:

So, from the question we have,

$x_1 = 0 , y_1 = 7 , x_2 = -7 and y_2 = 0$

From the distance formula,

Distance = $\sqrt{(-7 - 0 )^2 + (0- 7)^2}$

⇒Distance = $\sqrt{49 + 49}$ = $\sqrt{98}$ = 9 .89 units

And 9.89 can be written as 10 .

Final answer:

Hence, the distance between the given points is 10 units.

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