the distance between the points (10cos30,0)and (0,10cos60) is
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Let A(10 cos 30° ,0);B(0,10 cos 60°)
AB=√ (x2-x1)² + (y2-y1)²
=√(0- 10 cos 30 )²+( 10 cos 60)²
=√75+25
√100=10 sq.units
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