the distance between the points 3,1 and 0,x is 5.Find the value of x
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hello users ......
solution:-
Using distance formula ;
the distance between two points A(a,b) and B(c,d)
AB = √ (c-a)² + ( d- b)²
here,
distance between points A(3,1) and B(0,x) is 5
=> 5 = √ (0-3)² + ( x-1)²
=> 25 = 9 + x² +1 -2x
=> x² - 2x -15 = 0
=> x² -5x +3x - 15 = 0
=> x(x-5) +3(x-5) = 0
=> (x+3)(x-5) = 0
=> x+3 = 0 and x-5 = 0
=> x = -3,5 Answer
⭐✡ hope it helps ✡⭐
solution:-
Using distance formula ;
the distance between two points A(a,b) and B(c,d)
AB = √ (c-a)² + ( d- b)²
here,
distance between points A(3,1) and B(0,x) is 5
=> 5 = √ (0-3)² + ( x-1)²
=> 25 = 9 + x² +1 -2x
=> x² - 2x -15 = 0
=> x² -5x +3x - 15 = 0
=> x(x-5) +3(x-5) = 0
=> (x+3)(x-5) = 0
=> x+3 = 0 and x-5 = 0
=> x = -3,5 Answer
⭐✡ hope it helps ✡⭐
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