the distance between the points (3,4) and (6,0)
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Answered by
22
x1= 3, x2= 6, y1= 4, y2= -3 Distance between points
=V(x1- x2)^2 + (y - y2)^2
= = v(3-6)^2 + (4+3)^2
= v(-3)^2 + (7)^2
= v9 + 49
= V56
Answer = 214 units
Answered by
2
Answer:
Let d be the required distance.
∴d=
(3−6)
2
+(−2−4)
2
⇒d=
9+36
⇒d=
45
⇒d=3
5
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