The distance between the points (3k+1,-3k) and (3k-2,-4-3k)(in units ) is *
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Answer:
Distance
between two points (x
1
,y
1
) and (x
2
,y
2
) can be calculated using the formula
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
Distance between (3k,4) and (2,k)=
(3k−2)
2
+(4−k)
2
=
9k
2
+4−12k+16+k
2
−8k
=
10k
2
−20k+20
Given, distance between the points =5
2
=>
10k
2
−20k+20
=5
2
=>10k
2
−20k+20=25×2=50
=>k
2
−2k+2=5
=>k
2
−2k−3=0
=>k
2
−3k+k−3=0
=>k(k−3)+1(k−3)=0
=>(k+1)(k−3)=0
=>k=−1,3
Step-by-step explanation:
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