The distance between the points
(4, p) and (1,0) is 5 then the
value of p is
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p = -4
Step-by-step explanation:
Q) The distance between the points (4, p) and (1,0) is 5 then the value of p is
⇒ Given points (4,p) ; (1,0) and distance between them is 5.
We know that the formula for finding distance between two points
Let point A(4,p)≡(x1,y1) and B(1,0)≡(x2,y2)
d = √[(x2-x1)²+(y2-y1)²]
∴ d = √[ (1-4)² + (0-p)² ]
∴ 5 = √[ (-3)² + (-p)² ]
∴ 5 = √[ 9 + (-p)² ]
squaring on both side
∴ 5² = { [ 9+(-p)² ]^(1/2) }²
∴ 25 = [ 9+(-p)² ]^(2/2)
∴ 25 = [ 9+(-p)² ]^1
∴ 25 = [ 9+(-p)² ]
∴ (-p)² = 25 - 9
∴ (-p)² = 16
∴ (-p)² = 4²
∴ -p = 4
∴ p = - 4
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