Math, asked by karan4180, 1 year ago

The distance between the points (5,-3) and (8,1) is​

Answers

Answered by karpakavalli1974
11

Step-by-step explanation:

By using distence formula

 \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2}  }

x1=5,x2=8

y1=-3,y2=1

 \sqrt{(8  - 5) {}^{2}  + (1 -  3) {}^{2} }

 \sqrt{(3) { }^{2} + ( - 2) {}^{2} }

 \sqrt{9 + 4}

 \sqrt{13}

ans :3.60555

Answered by praneshhari20
16

Answer:

using distance formula

√(x2-x1)^2+ (y2-y1)^2

x1=5, x2=8.

y1 = -3, y2= 1.

√(8-5)^2+(1-(-3)^2

√3^2+4^2

√9+16

√25

=5

The distance is 5 units

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