Math, asked by akulapradeepkumar991, 10 months ago

The distance between the points (-6 and -2) on y-axis is
(A) 6 units (B) 6.2 units
(C) 2 units (D) 8 units

Answers

Answered by Anonymous
0

Answer:

using distance formula , the distance is 2 units.

Step-by-step explanation:

As we know tan A=Sin A/Cos A and tan B=Sin B/Cos B  So

tan squareA - tan squareB= (Sin A/Cos A)^2 - (Sin B/Cos B)^2 =

{(Sin^2 A Cos^2 B)-(Cos^2 A Sin^2 B)}/(Cos^2 A .Cos^2 B)

As we know that Sin^2 A=1-Cos^2 A and Sin^2 B=1-Cos^2 B ,So

tan squareA - tan squareB={( Cos^2 B(1-cos^2 A))-(Cos^2 A (1-Cos^2 B))}/(Cos^2 A .Cos^2 B)= (Cos^2 B- Cos^2 A)/(Cos^2 A .Cos^2 B)

Answered by surindarsingh037
1

Answer:

2 units is the correct answer

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