the distance between the points (a,1) and( 8,a) is 5 units
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hey mate
find here
the distance between the points (a,1) and( 8,a) is 5 units
distance =√[(8-a)²+(a-1)²]
5. = √[(8-a)²+(a-1)²]
25= (8-a)²+(a-1)²
64+a²-16a+a²+1-2a=25
2a²-18a+65-25=0
2a²-18a+40=0
a²-9a+20=0
a²-5a-4a+20=0
a(a-5)-4(a-5)=0
(a-5)(a-4)=0
so,
a-5=0. or. a-4=0
a=5. or. a=4.
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