Math, asked by avikav821, 1 day ago

the distance between the points (a,a) and (-√3a,√3a) is
ans - 2√2a units ​

Answers

Answered by pulakmath007
0

SOLUTION

TO DETERMINE

The distance between the points (a,a) and (-√3a,√3a)

CONCEPT TO BE IMPLEMENTED

For the given two points  \sf{A( x_1 , y_1) \:  \: and \:  \: B( x_2 , y_2)} the distance between the points

 =  \sf{ \sqrt{ {(x_2 -x_1 )}^{2}  + {(y_2 -y_1 )}^{2} } }

EVALUATION

Here the given points are (a,a) and (-√3a,√3a)

The distance between the points (a,a) and (-√3a,√3a)

 \sf =  \sqrt{ {(a +  \sqrt{3}a )}^{2} +  {(a -  \sqrt{3}a) }^{2}  }

 \sf =  a\sqrt{ {(1 +  \sqrt{3} )}^{2} +  {(1 -  \sqrt{3}) }^{2}  }

 \sf =  a\sqrt{2 \{ {(1 )}^{2} +  {( \sqrt{3}) }^{2} \}  }

 \sf =  a\sqrt{ 2(1 + 3)  }

 \sf =  a\sqrt{ 2 \times 4  }

 \sf =  2a\sqrt{ 2 }

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