Question

The distance between the points (a cos 0 + b sin 0, 0) and (0, a sin 0 – b cos 6), is
(a) a² +6² (6) a² – 6² (c) a² +6² (d) a² - 62​

Answer 1

Step-by-step explanation:

Given The distance between the points (a cos θ + b sin θ, 0) and (0, a sin θ – b cos θ), is

• The distance between the points is given by AB = √(x1 – x2)^2 + (y1 – y2)^2
•  AB = √(a cos theta + b sin theta – 0)^2 + ( 0 – (a sin theta – b cos theta))^2
•       = √a^2 cos^2 theta + b^2 sin^2 theta + 2ab sin theta cos theta +     a^2 sin^2 theta + b^2 cos^2 theta – 2 ab sin theta
•      = √a^2 (cos^2 theta + sin^2 theta) + b^2 (sin^2 theta + cos^2 theta)
•        = √a^2 + b^2  (since sin^2 theta + cos^2 theta = 1)

Reference link will be

https://brainly.in/question/8033510