The distance between the points (a cos θ + b sin θ, 0) and (0, a sin θ – b cos θ) is?
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Step-by-step explanation:
√(a^2+b^2) is the distance between the two points
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Answer:
√a²+b²
Step-by-step explanation:
let points be P and Q
√(x2-x1)² + (y2-y1)²
= [{0−(acosθ+bsinθ)}² + {(asinθ−bcosθ)−0}²]
=√ a ² cos² θ+ 2abcosθsinθ+b² sin²θ+b ²cos²θ−2absinθcosθ+a²sin²Ф
= √(a²+b²)cos²Ф + (a²+b²)sin²Ф
= √a²+b² [ sin²Ф +cos²Ф = 1]
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