Question

The distance between the points (a cos + b sinθ, 0) and (0, a sinθ - b cosθ) is (a) a + b (b) a 2 + b2 (c) a 2 – b 2 (d) √ 2+


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Answer 1

Answer:

$\sqrt{ {a}^{2} + {b}^{2} }$

Explanation:

$\sqrt{ {(acos \alpha + bsin \alpha )}^{2} + { (asin \alpha - bcos \alpha )}^{2} }$

$\sqrt{ {a}^{2} ( {sin}^{2} \alpha + {cos}^{2} \alpha) + {b}^{2}( {sin}^{2} \alpha + {sin}^{2} \alpha ) }$

$\sqrt{ {a}^{2} + {b}^{2} }$

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