the distance between the points (a cos0+b sin0,0) and (0,a sin0+b sin0) plss there is no minus in it
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Step-by-step explanation:
Given The distance between the points (a cos θ + b sin θ, 0) and (0, a sin θ – b cos θ), is
The distance between the points is given by AB = √(x1 – x2)^2 + (y1 – y2)^2
AB = √(a cos theta + b sin theta – 0)^2 + ( 0 – (a sin theta – b cos theta))^2
= √a^2 cos^2 theta + b^2 sin^2 theta + 2ab sin theta cos theta + a^2 sin^2 theta + b^2 cos^2 theta – 2 ab sin theta
= √a^2 (cos^2 theta + sin^2 theta) + b^2 (sin^2 theta + cos^2 theta)
= √a^2 + b^2 (since sin^2 theta + cos^2 theta = 1)
Step-by-step explanation:
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