Question

The distance between the points (a sin 60°,0) and (0,a cos 30°)

Answer 1

I think this should be the process

Answer 2

Answer: using distance formula,

=√(0-asin30)^2 + (asin60-0)^2

=√(a^2sin^230) + (a^2sin^260)

=√a^2(sin^230+sin^260)

=a√(1/4+3/4)

=a√1

=a