Question

The distance between the points (cosx, sinx) and (sinx ,-cosx
)​

Answer 1

Answer:

osx, sinx) and (sinx ,-cosx

Step-by-step explanation:

osx, sinx) and (sinx ,-cosx

Answer 2

The distance between the point (cosx, sinx) and (sinx ,-cosx)​ is $\sqrt{2(sin^{2}x +cos^{2}x)}$.

• A line segment is generally the pathway that joins two or more points. In order to find the distance between two points, we are basically finding the length of the line segment joining these two points.
• Except for when the points coincide with each other, distances in geometry are always positive. The distance between points A and B is equal to the square roots of the squares of the differences between their axes.

Now, according to the given information, we are given that,

The points are given as (cosx, sinx) and (sinx ,-cosx)​.

Now, in order to find the distance between these two points, we need to utilize the distance formula that is,

$\sqrt{(x_{2}- x_{1})^{2} +(y_{2}- y_{1})^{2} }$

Then, putting the values in this formula, we get,

$\sqrt{(sinx-cosx)^{2} +(-cosx-sinx)^{2} }\\=\sqrt{2(sin^{2}x +cos^{2}x)}$

Hence, the distance between the point (cosx, sinx) and (sinx ,-cosx)​ is $\sqrt{2(sin^{2}x +cos^{2}x)}$.

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