Question

The distance between the points L(5,-8),
& MC-7,-3) is.​

Answer 1

✬ The distance between the points is 13 units ✬

Step-by-step explanation:

Given: Distance between the points L(5,-8) and M(-7,-3)

To find: Distance between the points LM.

Required formula:

• Distance between two points = √(x₂ - x₁)² + (y₂ - y₁)²

❍ Let the points L(x₁,y₁) be (5,-8) and M be (x₂,y₂).

Then,

$\\ : \implies \sf{LM = \sqrt{ { \bigg( - 7 - 5 \bigg)}^{2} + { \bigg( - 3 - ( - 8) \bigg)}^{2} } } \\ \\ : \implies \sf{LM = \sqrt{ {( - 7 - 5)}^{2} + {( - 3 + 8)}^{2} }} \\ \\ : \implies \sf{LM = \sqrt{ {( - 12)}^{2} + {(5)}^{2} } } \\ \\ : \implies \sf{LM = \sqrt{144 + 25} } \\ \\ : \implies \sf{LM = \sqrt{169} } \\ \\ : \implies \underline{ \boxed{\frak{LM =13}}}\: \pink{ \bigstar}$

• Hence,The distance between the points LM is 13 units.