Question

..The distance between the points (m, n) and (-m, n) is
(a) m2 + m2 (b) m + n
(c) 27m2 + m2
(d) V2m + 2n
The centre of a circle whose end points of a diameter are (-6,3) and (6,4) is​

Answer 1

Step-by-step explanation:

distance between the points (m, n) and (-m, n)

here y coordintes are equal

so distance = | x2-x1 |

= | -m -m |

=| -2m |

= 2m

centre is the mid point of diameter

=( (-6+6)/2, (4+3)/2)

= (0, 7/2)