Question

the distance between the points p (2,3) and q (6,6) is​

Answer 1

Answer: 5 units.

Step-by-step explanation:

We know that the distance between points A(a,b) and B(c,d) is given by :-

$AB=\sqrt{(d-b)^2+(c-a)^2}$

Similarly, the distance between the points P (2,3) and Q (6,6) is​ given by :-

$PQ=\sqrt{(6-3)^2+(6-2)^2}\\\\\Rightarrow\ PQ=\sqrt{3^2+4^2}\\\\=\sqrt{9+16}\\\\=\sqrt{25}\\\\=\sqrt{5\times5}=5$

Hence, the distance between the points P (2,3) and Q (6,6) is​ 5 units.