Question

The distance between the points P(6,0) and Q(-2,0) is

Answer 1

Answer:

Please refer below....

Answer 2

The distance between the points P(6,0) and Q(-2,0) is 8 unit

Given :

The points P(6,0) and Q(-2,0)

To find :

The distance between the points P(6,0) and Q(-2,0)

Formula :

For the given two points ( x₁ , y₁) & (x₂ , y₂) the distance between the points

$= \sf{ \sqrt{ {(x_2 -x_1 )}^{2} + {(y_2 -y_1 )}^{2} } }$

Solution :

Step 1 of 2 :

Write down the given points

Here the given points are P(6,0) and Q(-2,0)

Step 2 of 2 :

Find the distance between the points

The distance between the points

= The distance between P(6,0) and Q(-2,0)

$\displaystyle \sf{ = \sqrt{ {( - 2 - 6)}^{2} + {(0 - 0)}^{2} } } \: \: unit$

$\displaystyle \sf{ = \sqrt{ {( - 8)}^{2} + {(0)}^{2} } } \: \: unit$

$\displaystyle \sf{ = \sqrt{ 64 + 0} } \: \: unit$

$\displaystyle \sf{ = \sqrt{ 64 } } \: \: unit$

$\displaystyle \sf{ = 8 } \: \: unit$

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