Question

The distance between the points P (6,0) and Q(2,0) is

a) 8 units b) 2 units c) 6 units d) 4 units​

Answer 1

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d) 4 units

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Answer 2

Answer:

option (d)

Step-by-step explanation:

P (6,0) and Q(2,0)

=>x₁ = 2 ; y₁ = 0

=> x₂ = 6 ; y₂ = 0

$The \ distance \ between \ two \ points =\sqrt{(x2-x1)^{2}+(y2-y1)^{2}} \\\\ y1 \ and \ y2 \ both \ are \ equal \ to \ zero(0)\\\\ PQ=\sqrt{(x2-x1)^{2}} \\PQ = (x2-x1)\\PQ=(6-2)\\PQ=4 \ units$