Question

The distance between the points P(-6 , 7) and Q(-1 , -5) is- * 1 point 14 units 12 units 13 units 11 units

Answer 1

$\textbf{Given:}$

$\text{Points are P(-6,7) and Q(-1,-5)}$

$\textbf{To find:}$

$\text{The distance between P and Q}$

$\textbf{Solution:}$

$\text{The distance between the two points is}$

$\mathrm{\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\text{The distance between P and Q}$

$\mathrm{=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\mathrm{=\sqrt{(-6+1)^2+(7+5)^2}}$

$\mathrm{=\sqrt{(-5)^2+(12)^2}}$

$\mathrm{=\sqrt{25+144}}$

$\mathrm{=\sqrt{169}}$

$\mathrm{=13}\;\text{units}$

$\textbf{Answer:}$

$\text{The distance between the points P(-6 , 7) and Q(-1 , -5) is 13 units}$

Answer 2

Answer:

sorry for the handwriting but

hope it helps you and clears your doubt!!