Question

The distance between the points P(x,-1)
and Q (3, 2) is 5 units. Find the value of x​

Answer 1

Given: Two points P(x,-1)  and Q (3, 2)

To find: The value of x?

Solution:

• Now we have given two points P(x,-1)  and Q (3, 2). The distance between them is 5 units.

• Now we know the distance formula as:

                   PQ = √{ ( x2 - x1 )^2 + ( y2 - y1 )^2 }

• So putting the values in formula, we get:

                   5 = √{ ( 3 - x )^2 + ( 2 - (-1) )^2 }

                   5 = √{ ( 3 - x )^2 + ( 2 + 1) )^2 }

• Squaring on both sides, we get:

                   25 =  ( 3 - x )^2 + 9

                   16 =  ( 3 - x )^2

                   ( 3 - x ) = 4,-4

                   x = -1 or x = 7

Answer:

            So the value of x is -1 or 7.