the distance between the points P(x,-y) and Q(-x,2y) is
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0
Answer:
_/4x^2-9y^2
Step-by-step explanation:
distance =√(x1-x2)^2-(y1-y2)^2
PQ=√{X+x}^2-(-y-2y)^2
PQ=√{2x}^2-(-3y)^2
PQ=√4x^2-9y^2
PQ=√(2x-3y)(2x+3y)
PQ=_/ (2x)^2-(3y)^2
PQ=_/ 4x^2-9y^2
Answered by
1
ho Saktha h ye wrong ho.....
most probably right
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