Math, asked by allanpaul9112006, 6 months ago

the distance between the points (tan a,1), (0,2) is​

Answers

Answered by DynamicPlayer
2

cos

4

x

+

θ

2

sin

4

x

=

θ

1

2

1

⇒(θ

1

2

)(

θ

1

cos

4

x

+

θ

2

sin

4

x

)=1

⇒(θ

1

2

)(

θ

1

cos

4

x

+

θ

2

sin

4

x

)=(sin

2

x+cos

2

x)

2

⇒(θ

1

2

)(

θ

1

cos

4

x

+

θ

2

sin

4

x

)=sin

4

x+cos

4

x+2sin

2

xcos

2

x

⇒(θ

1

2

2

cos

4

x+(θ

1

2

1

sin

4

x=θ

1

θ

2

sin

4

x+θ

1

θ

2

cos

4

x+θ

1

θ

2

2sin

2

xcos

2

x

⇒θ

2

2

cos

4

x+θ

1

2

sin

4

x−θ

1

θ

2

2sin

2

xcos

2

x=0

θ

1

θ

2

cos

4

x+

θ

2

θ

1

sin

4

x−2sin

2

xcos

2

x=0

θ

1

θ

2

cos

2

x

θ

2

θ

1

sin

2

x

2

=0

⇒tan

2

x=

θ

1

θ

2

Answered by ramkoti0001980
1

Answer:

Tan a+1

Step-by-step explanation:

distance between two points Answer is Tan a+1

Attachments:
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