Question

The distance between the pt P0,-2) and q(0,6)is (a)8 (b)6 (c)4 (d)2​

Answer 1

Answer:

8

Step-by-step explanation:by formula                       root(-2-6)^2

                                                                                     =root-8^2

                                                                                     =8

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Answer 2

Answer:

8 units

Step-by-step explanation:

according to distance formula,

$\sqrt{} {(x2 - x1) {}^{2} } + (y2 - y1) {}^{2}$

by by inserting we get it as root 64 that is 8.