Question

The distance between the rails of the track is 1.67 m. How much the outer rail be elecated for curve of 0.5km radius, so that a train moving with speed 54kmh^(-1) can take safe turn on track.

Answer 1

Answer:

Explanation:

Brainly.in

What is your question?

sumanmohapatra2003

Secondary School Physics 8+4 pts

A train has to negotiate a curve of 400m by how much the outer rail be raised with respect to inner rail for speed 48km/hr. The distance between rails is 1m?

Report by Taragarasha 27.09.2016

Answer

Radius of curved path is r. Width of path is b m. the outer edge is raised by h w.r.t inner edge so that a car with speed v can pass safe over it. the value of h is

tanθ = v²/rg=h/b

h=v ²b/rg

substituting the values according to given question,

v=48km/h =(48x 1000)/60x60m/s⇒40/3 m/s

b=1m

r=400m

g=9.8m/s2

h=(40/3)²x1/400x9.8

⇒0.0045m

⇒4.54cm