Question

the distance between the school and the house of the student is 1 km 875 m. every day she walks both ways between her school and home. find the total distance covered by her in a week..​

Answer 1

Answer:

Distance between school and home = 1875m Distance between home and school = 1875m

Total distance covered in one day = (1875m+1875m) = 3750m

Distance covered in six days = 3750 x 6 = 22500m

Therefore, 22 km 500 m distance covered in six days.

Answer 2

Given :–

• Distance between the school and the house = 1km 875m.
• Every day she walks both ways between her school and home.

To Find :–

• The total distance covered by her in a week.

Solution :–

First, we need to find the distance between the school and the house.

Given that,

Distance between the school and the house = 1km 875m

We know that,

• 1km = 1000m

So,

⟹ 1000m + 875m

⟹ 1875m

• Distance between the school and the house is 1,875m.

According to the question,

• She walks both ways.

She walks that distance twice in a day.

• Home to school.
• School to home.

Now, we need to find the distance covered in a day = 2 × 1875m

She walks 6 days because sunday is a holiday.

So,

The distance covered in 6 days = 2 × 6 × 1875m

⟹ 12 × 1875m

⟹ 22500m

• Total distance covered in 6 days = 22,500m

Now, convert km into m.

So, we know that,

• 1km = 1000m

⟹ 1m = $\dfrac{1}{1000}$

So,

⟹ 22500m = $\dfrac{22500}{1000}$

⟹ 22500m = 22km 500m

Hence,

The total distance covered by her in a week is 22km 500m