Question

The distance between the tip of the pole 10m and 18m high is 17m then the distance between their foot is

Answer 1

from the attached figure

in ∆ABC, AB = 8m , AC = 17 m

by Pythagoras theorem,

$AB^2 + BC^2 = AC^2$

$BC = \sqrt{AC^2 - AB^2}$

$\sqrt{ {17}^{2} - {8}^{2} } = \sqrt{289 - 64} = \sqrt{225} = 15$

BC = 15 m

since DE is the distance between two poles

DE = BC = 15 m