The distance between the top of two trees 20 m and 28 m high is 17 m the horizontal distance between the trees is
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Let there are two trees AB and CE whose heights are 20 m and 28 m respectively.
Now, AC = 17 m
CD = 28- 20 = 8 m
In right triangle CDE, we have
(AC)^2=(AD)^2+(CD)^2
(AD)^2=(AC)^2-(CD)^2
=17^2-8^2
=289 - 64
=225
AD=√225
AD=15m=BE
Hence, the distance between two trees is 15 m.
Now, AC = 17 m
CD = 28- 20 = 8 m
In right triangle CDE, we have
(AC)^2=(AD)^2+(CD)^2
(AD)^2=(AC)^2-(CD)^2
=17^2-8^2
=289 - 64
=225
AD=√225
AD=15m=BE
Hence, the distance between two trees is 15 m.
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ANSWER : AD = 15M=BE
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