Chemistry, asked by abhishekdhatrak34, 3 months ago

The distance between the two electrodes of the cell is 3 cm and area of
1 point
each electrode is 6 cm². The cell constant is-​

Answers

Answered by Gouta
2

Answer: this is the format only put correct valuae

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Explanation:

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Answered by syed2020ashaels
0

Answer:

The value of cell constant is 50m^{-1}

Explanation:

  • Distance between the two electrodes given to us is l=3cm
  • Area of each electrode is A = 6cm^2
  • Now as we know that the cell comstant E is given by
    E=\frac{l}{A}\\E = \frac{3}{6}\\ E=\frac{1}{2} \\E=0.5cm^-^1
  • Now E = 0.5 cm^{-1} and 1m = 100cm so
    E = 0.5*100m^-^1\\E=50m^{-1}
  • Hence the value of cell constant is 50m^{-1}
    #SPJ3
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