The distance between three consecutive troughs in a wave produced in a string is 4 cm. II 2.5 wave
cycles pass through any point in a second, the wave in the string has velocity V
1) 10 cm/s
(2) 0.16 cm/s
(3) 0.8 cm/s
(4) 5 cm/s
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12
velocity = frequency × wavelength
=2.5 × 4
= 10
(1) 10 cm/s
Answered by
0
Answer:
1 option is the answer .
Explanation:
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