Question

the distance between two bodies becomes 6 times more than usual distance . the F becomes

Answer 1

The gravitational force will increase 16 times. ... If the distance between two objects is halved, and the mass of one of the objects ... If your distance is cut in half, your R² becomes 1 /

Answer 2

Explanation:

It is given that, the distance between two bodies becomes 6 times more than usual distance. The actual force is given by :

$F=G\dfrac{m_1m_2}{r^2}$

r is the distance between two bodies.

$F\propto \dfrac{1}{r^2}$

New force is :

$F'=G\dfrac{m_1m_2}{r'^2}$

Here, r' = 6 r

$F\propto \dfrac{1}{(6r)^2}$

$F'=\dfrac{Gm_1m_2}{36r^2}$

$F'=\dfrac{1}{36}F$

The new force reduces to (1/36) times than the initial force. Hence, this is the required solution.