Question

The distance between two bodies becomes 6 times more than the usual distance. Then the F becomes

Answer 1

F=(G×M1×M2)/d²
When distance is becomes 6 times
F=(G×M1×M2)/6²
F=(G×M1×M2)/36
F is inversely proportional to the distance
Hence if distance becomes 6 times then F is decreased by factor 36

Answer 2

Answer:

F is 36 times F₂

Explanation:

m₁ =  Mass of one object

m₂ =  Mass of other object

r = Distance between the objects

G = Gravitational constant

$F=G\frac{m_1m_2}{r^2}$

$F=G\frac{m_1m_2}{(6r)^2}\\\Rightarrow F_2=G\frac{m_1m_2}{36r^2}$

Dividing the equations we get

$\frac{F}{F_2}=\frac{G\frac{m_1m_2}{r^2}}{G\frac{m_1m_2}{36r^2}}\\\Rightarrow \frac{F}{F_2}=36\\\Rightarrow F=36F_2$

F is 36 times F₂