Math, asked by chandanrider2002, 3 months ago

the distance between two cities A and B is 425 km. If a car leaves A at 2 p.m. and reaches B at 10.30 p.m., what is the speed of the car?

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Answers

Answered by jasmin68
3

Step-by-step explanation:

Time taken by the car = 10 : 30 P.M. - 2 P.M.

= 8 hours 30 minutes

= 8.5 hours

Distance = 425 Km

⟹Speed=

8.5

425

⟹Speed=50Km/Hour

Answered by Anonymous
2

Answer:

speed = distance ÷ time

425 km ÷ 8.5 hrs = 50 km per hars

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