the distance between two cities A and B is 425 km. If a car leaves A at 2 p.m. and reaches B at 10.30 p.m., what is the speed of the car?
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Answers
Answered by
3
Step-by-step explanation:
Time taken by the car = 10 : 30 P.M. - 2 P.M.
= 8 hours 30 minutes
= 8.5 hours
Distance = 425 Km
⟹Speed=
8.5
425
⟹Speed=50Km/Hour
Answered by
2
Answer:
speed = distance ÷ time
425 km ÷ 8.5 hrs = 50 km per hars
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