The distance between two cities And B is 510km. A train t1 leaves A towards B at 2:45 pm which a speed of 50km/hr.it meets the train t2 which leaves B at 1:35pm and moving at a speed of 60kmph towards A.the distance travelled by t1 by the time it met t2 is
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Correct Answer:
200 km
Description for Correct answer:
Let the two trains meet at x km from Mumbai.
Then, 3:45 pm +x50=2:35 pm +510−x60
=> (3:45 pm −2:35 pm)+(x50+x60)=51060
=> (116h)+x(50+6050×60)=172
=> x(1103000)=172−76
=> x(1103000)=51−76=446
Therefore, x=446×3000110 = 200 km
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Answer:
THE ANSWER IS 200 km!
Description for Correct answer:
Let the two trains meet at x km from Mumbai.
Then, 3:45 pm +x50=2:35 pm +510−x60
=> (3:45 pm −2:35 pm)+(x50+x60)=51060
=> (116h)+x(50+6050×60)=172
=> x(1103000)=172−76
=> x(1103000)=51−76=446
Therefore, x=446×3000110 = 200 km
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