The distance between two consecutive troughs produced in a string is 4cm. If 2.5 wave cycles through any point in a second, What is the velocity of the string
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velocity of the string = frequency x wavelength
velocity of the string = 2.5 × 4
= 10 m/sec
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Answer:
0.1 m/s
Explanation:
The distance between two consecutive trough or crest is known as the wavelength of the wave which is given in the question as 4 cm.
λ = 4 cm
No of oscillation per unit time is frequency of the wave. So frequency is,
ω = 2.5
The velocity of the wave is v=(/omega) (/lambda) = 2.5×0.04 =0.1 m/s
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