the distance between TWO LINES 5X+3y=7 AND 15X+9Y+14=0 IS
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Answer:
7/3√34
Step-by-step explanation:
5x+3y=7. (1)
15x+9y=-14
=> 5x+3y=-14/3. (2)
then d=|7--14/3|/(√25+9)
=7/3√34
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