Question

The distance between two parallel chords of length 10 cm each in a circle of diameter 26 cm is​

Answer 1

ANSWER

Let AB=8 cm is the chord of the circle with radius 5 cm

Draw OP⊥AB and join BO

PB=21AB=21×8=4cm

In △BPO∠P=90∘

∴OB2=PB2+OP2

⇒OP2=OB2−PB2

⇒OP=52−42

⇒OP=25−16⇒9=3cm.

Let CD=6 cm is the chord of the circle with radius 5 cm

Draw OQ⊥CD and join DO

QD=21CD=21×6

Answer 2

Step-by-step explanation:

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