The distance between two parallel chords of length 10 cm each in a circle of diameter 26 cm is
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Let AB=8 cm is the chord of the circle with radius 5 cm
Draw OP⊥AB and join BO
PB=21AB=21×8=4cm
In △BPO∠P=90∘
∴OB2=PB2+OP2
⇒OP2=OB2−PB2
⇒OP=52−42
⇒OP=25−16⇒9=3cm.
Let CD=6 cm is the chord of the circle with radius 5 cm
Draw OQ⊥CD and join DO
QD=21CD=21×6
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