Question

the distance between two parallel lines y=2x+4 and 6x=3y-5 is ? ​

Answer 1

Step-by-step explanation:

$Given \: it \: \\ 2x - y + 4 = 0 \\ 6x - 3y + 5 = 0 \\ \\ Distance \: between \: parallel \: lines \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{ \sqrt{4 + 1} } - \frac{5}{ \sqrt{36 + 9} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{ \sqrt{5} } - \frac{5}{3 \sqrt{5} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{12 - 5}{3 \sqrt{5} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{7}{3 \sqrt{5} } units \\ \\ Hope \: it \: will \: help \: you.$