Math, asked by khushi449898, 1 year ago

The distance between two parallel planes 2x+y+2z=8 and 4x+2y+4z=4is:
(1)1
(2)2
(3)3
(4)4

Answers

Answered by Anonymous

Answer: 2

Step-by-step explanation:

khushi449898: hello bhai

Anonymous: hello

khushi449898: apne toh shirff ans bata diya, solve kaise kiya h plz tell me

Anonymous: d=|d2-d1|/root(a^2+b^2+c^)=|2-8|/root(2^2+1^2+2^2)=6/root(9)=6/3=2

khushi449898: thanks bro

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