The distance between two particles of masses 2 kg and 4 kg is r. Their distances from
the centre of mass of the system are r1 and r2 respectively. Then, r1r2
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Answer:
Given, Two masses M1=4kg,m2=2kg
So the net force at the point is:
F=m1g−m2g=4g−2g=2×10=20N
Acceleration on the center of mass is:
a=m1+m2F=2+420=310m/s2
a) Distance traveled in 9s
S=21at2=21×310×92=135m
b) The Speed of the CoM in 9s
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the spead COM in 9sec
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