The distance between two pillars is 120 metres. the height of one pillar is thrice the other. the angles of elevation of their tops from the midpoint of the line connecting their feet are complementary to each other. the height (in metres) of the taller pillar is
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In ABC,
tan theta = AB/BC = x/60.........(1)
In CDE,
cot (90-theta) = CD/DE = 60/3x
tan theta = 20/x...........(2)
Equating (1) and (2), we get,
x/60 = 20/x
x^2 = 1200
x = 20√3 m
3x = 20√3 × 3 = 60√3 m
Hope this helps!!!!!
Plsss make it the brainiest
tan theta = AB/BC = x/60.........(1)
In CDE,
cot (90-theta) = CD/DE = 60/3x
tan theta = 20/x...........(2)
Equating (1) and (2), we get,
x/60 = 20/x
x^2 = 1200
x = 20√3 m
3x = 20√3 × 3 = 60√3 m
Hope this helps!!!!!
Plsss make it the brainiest
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