Question

The distance between two places A and B is 300 km. Two scooterist’s start simultaneously from

A and B towards each other. The distance between them after 2

1

2 hours is 25km. If the speed of

one scooterist is 10km/hr higher than the other, find the speed of each of them.



please explain and answer.​

Answer 1

Answer:

let the two scooterist be A and B

let speed of A =x ,and speed of B =x+10

after 2 hours,

distance covered by A=5/2x

and distance covered by B=5/2(x+10)

ATQ(according to the question),

"5/2x+5/2(x+10)+25=300"

=5/2x+5/2x+25+25=300

=10/2x=300-50

=10/2x=250

=x=250×2/10

=x=50

hence,

speed of scooterist A=x=50km/hr

and speed of scooterist B=x+10=60km/h

thanku ,hope it helps u,

Step-by-step explanation:

Answer 2

Answer:

Let speed of scooter starting from A be x km/hr and from B be (x + 10) km/hr

⇒ Relative speed = x + x + 10 = 2x + 10 km/hr

⇒ Distance covered in 2.5 hr = Time × Relative speed = 2.5 × (2x + 10) = 5x + 25

According to question,

⇒ 5x + 25 = 300 - 25

⇒ x = 50

∴ Speed of scooters are 50 and 60 km/h