The distance between two places A and B is 300km. Two scooterists start simultaneously from and b towards each other. The distance between them after 2.5 hours is 25km. If the speed of one scooterist is 10km/hr than the other find the speed of each of them
Answers
Answer: 120
Step-by-step explanation:
well you have to divide by 300 2.5 witch would be 120
Given data :-
- The distance between two places A and B is 300km.
- Two scooterists start simultaneously from A and B towards each other.
- The distance between them after 2.5 hours is 25km.
- The speed of one scooterist is 10 km/hr more than the other.
Solution :-
Let, first scooterist be P and second scooterist be Q
Let, speed of scooterist Q = x km/hr .....( 1 )
Hence, according to given
{The speed of one scooterist is 10 km/hr than the other}
→ Speed of scooterist P = {x + 10} km/hr .....( 2 )
The distance between them after 2.5 hours is 25km. hence,
→ Total distance travel by A and B before 2.5 hour = {300 - 25 } km
→ Total distance travel by A and B before 2.5 hour = 275 km .....( 3 )
→ Total time taken by A and B to cover 275 km = 2.5 hour .....( 4 )
Now, we use formula of relative speed
→ Relative speed of A and B
= {Total speed}/{Total time}
[from ( 1 ), ( 2 ), ( 3 ) & ( 4 )]
→ x + x + 10 = 275/2.5
→ 2x + 10 = 110
→ 2x = 110 - 10
→ 2x = 100
→ x = 100/2
→ x = 50 km/hr
Hence, speed of scooterist Q is 50 km/hr.
Put value of x in eq. ( 2 )
→ Speed of scooterist P = x + 10
→ Speed of scooterist P = 50 + 10
→ Speed of scooterist P = 60 km/hr
Hence, speed of scooterist P is 60 km/hr.
Hence, speed of scooterist P and Q is 60 km/hr and 50 km/hr respectively.