Question

the distance between two point A and B is 100 metre a person with travels a speed of 20 metre per second. calculate average speed and average velocity​?​

Answer 1

Correct QuEstion:

The distance between two point A and B is 100 metre a person travels with a speed of 20 metre per second. Calculate average speed and average velocity.

ProvidEd that:

• Distance = 100 metres
• Speed = 20 metre per second

To calculaTe:

• Average speed
• Average velocity

SolutioN:

• Average speed = 20 m/s
• Average velocity = 20 m/s

UsiNg concepts:

• Average speed formula
• Average velocity formula
• Formula to calculate time

UsiNg formulas:

${\small{\underline{\boxed{\sf{\star \: Average \: speed \: = \dfrac{Distance}{Time}}}}}}$

• ${\small{\underline{\boxed{\sf{v \: = \dfrac{s}{t}}}}}}$

${\small{\underline{\boxed{\sf{\star \: Average \: velocity \: = \dfrac{Displacement}{Time}}}}}}$

• ${\small{\underline{\boxed{\sf{v_{av} \: = \dfrac{s}{t}}}}}}$

${\small{\underline{\boxed{\sf{\star \:Time \: = \dfrac{Distance}{Speed}}}}}}$

• ${\small{\underline{\boxed{\sf{t \: = \dfrac{s}{v}}}}}}$

Where, s denotes distance or displacement, ${\sf{v_{av}}}$ denotes average velocity, v denotes average speed, t denotes time

RequirEd solution:

~ Firstly let us find the time taken!

$:\implies \sf Time \: = \dfrac{Distance}{Speed} \\ \\ :\implies \sf t \: = \dfrac{s}{v} \\ \\ :\implies \sf t \: = \dfrac{100}{20} \\ \\ :\implies \sf t \: = \dfrac{10}{2} \\ \\ :\implies \sf t \: = 5 \: s \\ \\ :\implies \sf Time \: = 5 \: seconds$

~ Now let us find average speed!

$:\implies \sf Average \: speed \: = \dfrac{Distance}{Time} \\ \\ :\implies \sf v \: = \dfrac{s}{t} \\ \\ :\implies \sf v \: = \dfrac{100}{5} \\ \\ :\implies \sf v \: = 20 \: ms^{-1} \\ \\ :\implies \sf Average \: speed \: = 20 \: ms^{-1}$

~ Now let's find average velocity!

Knowledge required: Displacement is the shortest distance between two points!

Here, the displacement is 100 m itself!

$:\implies \sf Average \: velocity \: = \dfrac{Displacement}{Time} \\ \\ :\implies \sf v_{av} \: = \dfrac{s}{t} \\ \\ :\implies \sf v_{av} \: = \dfrac{100}{5} \\ \\ :\implies \sf v_{av} \: = 20 \: ms^{-1} \\ \\ :\implies \sf Average \: velocity \: = 20 \: ms^{-1}$

Average speed is 20 m/s and average velocity is 20 m/s also!

Explore more:

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Speed&\bf Velocity\\\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}&\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}\\\sf The \: distance \: travelled \: by &\sf The \: distance \: travelled \: by \\ \sf \: a \: body \: per \: unit \: time&\sf \: a \: body \: per \: unit \: time \\ &\sf in \: a \: given \: direction \\\\\sf It \: is \: scalar \: quantity. &\sf It \: is \: vector \: quantity \\\\\sf It \: is \: positive \: always &\sf It \: can \: be \: \pm \: \& \: 0 \: too \\\\\sf Speed \: = \dfrac{Distance}{Time} &\sf Velocity \: = \dfrac{Displacement}{Time} \end{array}}\end{gathered}$

• Dear app users, if you are getting problem to see the difference from app then you can go to web or can see it from attachment 1st too!

• Diagram regards this question, refer to attachment 2nd! Thanks for understanding!